The graph of y = x 3 is symmetric about the origin, which indicates that it has rotational symmetry. If you rotate the graph 180 degrees around the origin, it looks the same. By plotting the points mentioned and drawing a smooth curve connecting them, you can visualize the graph of y = x 3. You will see that it passes through the origin (0, 0 ...
We designate (3, 5) as (x 2, y 2) and (-4, 2) as (x 1, y 1). Substituting into Equation (1) yields. Note that we get the same result if we subsitute -4 and 2 for x 2 and y 2 and 3 and 5 for x 1 and y 1. Lines with various slopes are shown in Figure 7.8 below.
Answer to: Graph y=x^3 By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can also ask your own homework...
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Hint: In order to draw the graph for any equation we need to find the local maxima and local minima and where it touches the x-axis and y-axis. Also take some sets of (x,y) by taking x as(-2,-1,0,1,2) to see how a certain graph is going up or down and also find the inflection points. Complete step-by-step solution: Given that the graph is $ y=x ...
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You should plug in any number for x which can be positive or negative numbers. Explanation: graph{y=-x-3 [-10, 10, -5, 5]} So you can plug in any numbers for x.
Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Enter a problem... Algebra Examples. Popular Problems. Algebra. Graph Using a Table of Values y=x-3. ... This is a table of possible values to use when graphing the equation ...
It's a V shaped graph with the bottom of the V at (3,0) which is the x intercept. It's symmetric about x = 3. the right side of the V is a diagonal line 45 degrees with the x axis, a slope = 1. the left side of the V is a diagonal line 135 degrees with the x axis, slope = -1. The graph is two lines, one is y=x-3 and the other y=-x+3, but only ...
Y=-3 so, the pair (0,-3) is a solution. Substitute y=0 and solving to get x=3 So the pair (3,0) is a solution. We obtained two points which are (0,-3) and (3,0). According to Euclid's axiom there is only one line which pass through this point which is going to be the line of the equation. On a graph paper, draw the axes and plot these two points.
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And $(\star)$ or $(\frac23(\frac{a^2+ab+b^2}{a+b}),2\frac{a^2b^2}{a+b})$ only fills the first quadrant below the curve and the third quadrant above the curve, as we can see by $$(\zeta-a)(\zeta-b)(\zeta-c)=\zeta^3-(a+b+c) \zeta^2+ (ab+ac+bc)\zeta-abc\\=\zeta^3-\frac32 x_0 \zeta^2+0\zeta+\frac12 y_0$$ having discriminant $$-27 y_0 (y_0-x_0^3 ...
Mathematics document from Zayed University, 15 pages, AP CALCULUS AB Test Booklet 1.3 1. The graph of the function f is shown above. Which of the following statements must be false? (A) f(a) exists. (B) f(x) is defined for 0 < x < a. (C) f is not continuous at x = a. (D) exists. (E) exists. 2. The graph of y
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Remember that the y-intercept of a line is always written as an (x,y) coordinate where x is 0. Final Answer: The line has an equation of y=2x + 1 and the y-intercept is at (0,1) Figure 02 shows the step-by-step process for solving this first problem, and Figure 03 shows the graph of y=2x+1 (notice how the line passes through the two given ...