The equivalent resistance of nine bulbs connected in series is 9R. The current is \(I = V/9 \, R\). If one bulb burns out, the equivalent resistance is 8R, and the voltage does not change, but the current increases \((I = V/8 \, R\). As more bulbs burn out, the current becomes even higher.
Equivalent resistance of the following network is ___ Ω. asked Feb 17, 2024 in Physics by SivaSireesha (47.8k points) jee main 2024; Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries.
The equivalent resistance between points A and B is approximately 4.00 Ω. Highlights. Breaking down the circuit into smaller, manageable series and parallel combinations is crucial. Paying attention to detail and ensuring accurate calculations at each step is important.
Hence equivalent resistance between points A and B is 22.5Ω. Additional information: Resistance in series: when a several number of resistances are connected in series then the equivalent resistance is equal to sum of individual resistances. If ${{R}_{1}},{{R}_{2}},{{R}_{3}}$ be the resistor connected in series than their equivalent resistance ...
The resistance R 2 and R 3 are in series combination. Therefore their equivalent resistance. R'= R 2 + R 3 =10+10 = 20 Ω. Similarly, the resistance R 5 and R 6 are in series combination. Therefore their equivalent resistance, R"= R 5 + R 6 = 10+10 = 20 Ω. Now the equivalent resistances R' and R" are in parallel combination. Therefore their ...
JEE Main 2023: The equivalent resistance between A and B is (A) (2/3) Ω (B) (3/2) Ω (C) (1/3) Ω (D) (1/2) Ω. Check Answer and Solution for above q
The equivalent resistance of the circuit network across A and B is \[\dfrac{r}{2}\Omega \]. This is the required solution. Note: The resistance of a network is dependent on the type of combination of resistors. From this example, we understand that the resistance can be even lesser than the resistances involved in the circuit.
Therefore, equivalent Resistance between A and B is 5Ω. ← Prev Question Next Question →. Find MCQs & Mock Test. JEE Main 2026 Test Series ...
The equivalent resistance of two resistors in parallel is given by the formula: R e q = R 1 + R 2 R 1 ⋅ R 2 After finding the equivalent resistance of the parallel resistors, we will add the series resistors to find the total equivalent resistance. Step-By-Step Solution Step 1. Identify the resistors in parallel.
Find the equivalent resistance between points A and B in the drawing. Always start away from where you are trying to find the resistance between. So we begin by combining the 1 Ω, 2 Ω, and 3 Ω in series. Our circuit becomes. Now we combine 3 Ω and 6 Ω as parallel resistors . Our circuit now looks like
CONCEPT: Equivalent Resistance: Equivalent Resistance between two Points is the ratio of Potential Difference between them and the amount of current passing through them. Equivalent Resistance can also be defined as the resistance of the resistor which will replace all the resistors between two points and will draw the same current between these two points as it was flowing Earlier.
How to manually calculate equivalent resistance. To calculate the equivalent resistance of a cicuit you have to seperate groups of components into series and parallel. Parallel components share the same voltage while series components share the same current. The equivalent resistance for special cases like Y and Delta circuits can also be ...
This group of resistors will act like one equivalent resistor. What is its resistance? Part 1. Redraw The Circuit + 1A. Circuit transformation. Circuit diagrams are an abstraction of a real circuit, there are many ways to draw and redraw them. This example shows you how to redraw circuit diagrams to suit out purposes
The statement of the problem is straightforward, find the equivalent resistance. but The question seems at first a little absurd. It's the same resistors, why should the resistance be different? It turns out they will be very different. We start with two circuits that look very similar. I'll be refering to "Circuit AB" and "Circuit BC" to label ...
Since we know the power loss and voltage of the circuit, we can calculate the equivalent resistance of the circuit using the following equations: Substituting Ohm's law into the equation for power, we get: Rearranging for resistance, we get: This is the equivalent resistance of the entire circuit.
The equivalent resistance of the network of resistors is . Exercise: Determine the equivalent resistance of the circuit shown if all resistances have a value of . Figure 3.8a . Solution: We begin by noting that and are in series and the series combination of these two resistors is in parallel with and . This can be seen more clearly when the ...
Triangle Resistors Equivalent Resistance. Here, let’s consider the base nodes 1 and 2. In between nodes 1 and 2, there are two paths for resistors, 12 and 132. So these two would be parallel. Therefore the two resistors in path 132 are connected in series, the equivalent resistance is R + R = 2R.
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