Consider x^ {2}+2x-3. Factor the expression by grouping. First, the expression needs to be rewritten as x^ {2}+ax+bx-3. To find a and b, set up a system to be solved.
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Click here 👆 to get an answer to your question ️ Factorise the following. -3x^2+6x+9
Factor completely.$-3x^{2}+6x+9=\\square $Related contentFactoring quadratic with a common factorWatch the full video with step-by-step explanation at: https:...
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To factor the quadratic expression -3x^ {2}+6x+9 −3x2 +6x +9 completely, we need to find two numbers that multiply to give the product of the coefficient of x^2 x2 (which is -3) and the constant term (which is 9), and add up to the coefficient of x (which is 6).
The expression −3x2 +6x −9 can be factored by taking out the greatest common factor, which is -3, resulting in −3(x2 − 2x + 3). Furthermore, the quadratic x2 − 2x + 3 cannot be factored further using real numbers. Thus, the complete factored form remains as −3(x2 − 2x + 3).
Sure, I'd be happy to help you factor the quadratic expression −3x² + 6x − 9 completely. Step 1: Factor out the Greatest Common Factor (GCF) The first step in factoring an
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Detailed step by step solution for factor 3x^2-6x+9
Learn how to solve polynomial factorization problems step by step online. Factor the expression 3x^2+6x+9. Factor the polynomial 3x^2+6x+9 by it's greatest common factor (GCF): 3.
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Factor the quadratic: Now, focus on factoring the quadratic expression inside the parentheses, x2−2x−3. Find two numbers that multiply to -3 and add to -2: We need two numbers whose product is −3 (the constant term) and whose sum is −2 (the coefficient of the middle term).
Find step-by-step Algebra 2 solutions and your answer to the following textbook question: Factor completely. -3x2+6x+9=.
Now, focus on factoring the quadratic inside the parentheses: x2−2x−3. We will look for two numbers that multiply to −3 (the constant term) and add to −2 (the coefficient of the linear term).
